16b^2+40b+25=0

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Solution for 16b^2+40b+25=0 equation: 



16b^2+40b+25=0

a = 16; b = 40; c = +25;
Δ = b2-4ac
Δ = 402-4·16·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{-40}{32}=-1+1/4$

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